An airplane covered 19 miles of its route while decreasing its altitude by 41,000 feet. Find the slope of the airplane's line of descent. Round to the nearest hundredth. [Hint: 1 mi = 5280 feet.]
2007-09-02 05:02:13 · 8 answers · asked by ? 2 in Science & Mathematics ➔ Mathematics
How did you get the snswer???
2007-09-02 05:11:20 · update #1
Hi,
If the plane covered 19 miles, that, in feet, is 19 x 5280 = 100,320 feet. If it descended 41000 feet as it covered those 100,320 feet then tan A = opposite/adjacent = 41000/100320 = .40869. This is the slope. To find the angle A, find the arc tan(.40869) which is 22.23°. That is the angle of descent.
I hope that helps!! :-)
2007-09-02 05:09:15 · answer #1 · answered by Pi R Squared 7 · 0⤊ 2⤋
The slope is the change in altitude with the chnage in distance. It is a negative number due to the descent.
slope = - 41000/19/5280
2007-09-02 05:10:37 · answer #2 · answered by Scott H 3 · 0⤊ 0⤋
slope =y/x = 41000/19*5280 = .408692185 = .41
Since the plane is descending the slope i s -.41
2007-09-02 05:18:19 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
slope = -41,000/(19*5280) = -0.41
The negative slope refers to landing.
2007-09-02 05:09:22 · answer #4 · answered by sahsjing 7 · 0⤊ 0⤋
This question can be interpreted in two ways:-
1. Hypotenuse = 19 miles
2. Horizontal = 19 miles
Slope = tan θ
Altitude = 7.77 miles
Method 1
sin θ = 7.77 / 19
θ = 24 . 1°
tan 24.1° = 0.448
slope = 0.448
Method 2
tan θ = 7.77 / 19
m = 0.409
It depends if the 19 miles is taken as horizontal or hypotenuse.
2007-09-05 22:18:17 · answer #5 · answered by Como 7 · 0⤊ 0⤋
Slope is a tangent relation.
-41,000 foot:[(19 mile)(5280 foot/mile)].
2007-09-02 05:43:07 · answer #6 · answered by Mark 6 · 0⤊ 0⤋
slope = descent/distance
= 41000 ft/19 miles
= 41000 ft / 19*5280 ft
= 0.40 = 2/5
2007-09-02 05:09:23 · answer #7 · answered by sv 7 · 0⤊ 1⤋
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2016-12-12 16:01:22 · answer #8 · answered by ? 4 · 0⤊ 0⤋