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y = (5-x)^(1/3)

FInd the inverse function.
Enter the RHS(right-hand-side) of the function.

2007-09-02 03:43:05 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

what u are doing is reflectign the line in y=x , thats what inverse means so first you have to swap y for every x in teh given equation.

x= (5-y)^(1/3)

then what you have to do is to get y on its own so that it look s like an equation

.........x^3=5-y
5-x^3 =y

2007-09-02 03:50:47 · answer #1 · answered by a c 7 · 1 0

y = f(x) = (5-x)^(1/3)
let x = g(y) = f^-1(y), the inverse function

y^3 = 5 - x
so
x = 5 - y^3

2007-09-02 10:47:51 · answer #2 · answered by vlee1225 6 · 0 0

Ok, let's see...

- Raise each side of the equation to the third power

y^3 = 5-x

- rearranging terms,

x = 5-y^3

Good luck!

2007-09-02 10:48:21 · answer #3 · answered by alrivera_1 4 · 0 0

y = (5-x)^(1/3)
If possible, just solve for x.
ln y = 1/3 ln (5-x)
3lny = ln(5-x)
e^(3lny) = 5-x
x = 5 - e^(3lny) <-- Inverse

2007-09-02 11:05:09 · answer #4 · answered by ironduke8159 7 · 0 0

interchange x and y
y = (5-x)^(1/3)

x=(5-y)^(1/3)
x^3=5-y
y=5-x^3

2007-09-02 10:48:49 · answer #5 · answered by ptolemy862000 4 · 1 0

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