determine a value of a so that each point named is on the graph of.
1. f(x)= ax^2
a, (2,2)
2. f(x)= ax^2 - 2x + 3
a. (3,2)
3. f(x)= a(x+1)^2 - 5
a. (4,0)
thankssss
2007-09-02 00:25:30 · 5 answers · asked by xah8 1 in Science & Mathematics ➔ Mathematics
1. 2=ax2^2
2=ax4
a=1/2
2. 2=a3^2-2x +3
2=a9-6+3
5=ax9
a=5/9
3. 0=a( 4+1)^2-5
5=a25
a=5/25=1/5
2007-09-02 01:17:49 · answer #1 · answered by just4 2 · 0⤊ 0⤋
f(x)=ax^2
a)()2,2; 2=a*4,a=1/2.ANS
b) f(x)= ax^2-2x+3
point (3,2); 2=9a-6+3
9a=5,a=5/9.ANS.
c). f(x)=a(x+1)^2-5
point (4,0);
0=a*25-5
25a=5
a=5/25=1/5 ANS.
2007-09-02 08:53:13 · answer #2 · answered by Anonymous · 0⤊ 0⤋
1. set a=1/2 x=2
2. set a=2 x=3
3. set a=1/5 x=4
if point sets are x then y ie (x,y)
2007-09-02 07:36:33 · answer #3 · answered by charliefromwashington 3 · 0⤊ 1⤋
1)
2=a2^2
a=2/4=1/2
2)
2=a9-6+3
a=5/9
3)
0=a25-5
a=5/25=1/5
2007-09-02 07:32:05 · answer #4 · answered by iyiogrenci 6 · 1⤊ 0⤋
substitute the value of given co-ordinates in the given eqn.
solve for a from there .
2007-09-02 07:52:27 · answer #5 · answered by calculus 1 · 0⤊ 0⤋