How to do this?

Question

ok so i need help with math problems because i have no idea what the problems are asking me to do

its says write an equivalent experession
4+m
9y
3a+5

how to i write the equivalent problem? use different numbers move them around?
give direction and answers

also how to write using an exponential notation?

n times n times 2 times n times n

and 5 times c times c times ctimes c

thanx in advance

Answer 1

im not sure some of my answers. but i hope these helps...

4+m = m+4
9y = 3 * 3y
3a+ 5 = 5+3a

n*n*2*n*n = 2 * n^1* n^1* n^1* n^1 = 2 * n^4 = 2n^4

5*c*c*c*c = 5 * c^1* c^1* c^1* c^1 = 5 * c^4 = 5c^4

Answer 2

There is no single best answer to the equivalent expressions problems. For example,
4 + m = 3 + m + 1 = (8/2) + m =2 + 3 - 1 + 2*(m/2), and so on. You are merely being asked to write ANYTHING which is equal to the given expression. I'm not surprised you are confused--these are stupid questions.

On the other hand, the questions about exponential notation have unique answers if usual conventions are followed. Other responders have answered these questions correctly.

Answer 3

First the equivalent expression, the 9y can be divided into 3* 3y, and I think the other two can be multiplied to give equivalent expressions ex: 4+m = 2(4+m) = 8+ 2m.

When you have muliple of letter, just count the number of letters and put that number in the exponent ex: n*n*2*n*n has 4n therefore the answer is 2n^4.

Answer 4

4 + m = m + 4
9y = 9*y = 3*3*y = y*3*3 =
(3^2)y = y (3^2)

3a + 5 = 3*a + 5 = 5 + 3*a =
3(a+5/3) = 5(3/5*a+1)

n times n times 2 times n times n =
[{(n^n)^2}^n]^n

and 5 times c times c times c times c=
[[{(c)^c}^c]^c]^5

Answer 5

dunno you got me on that