anything between -1 and 1
2007-09-01 23:59:33
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answer #1
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answered by Mugen is Strong 7
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Neither is defined. One may be asked to consider
lim (x->inf)sin x , but that limit does not exists because sin x takes on every value between -1 and 1 as x increases without bound. Same for cos x.
2007-09-02 01:22:18
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answer #2
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answered by Tony 7
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It is just a finite value between 1 and -1....but u can't tell the exact value.....whatever u put in sin and cos functions....they just lie from -1 to 1.....infinity may yield anything between them.
2007-09-01 21:25:33
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answer #3
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answered by nik_gupta2006 1
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Undefined.
2007-09-01 21:05:02
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answer #4
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answered by symzeiss 1
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it could be 1 or -1
2007-09-01 21:11:28
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answer #5
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answered by ptolemy862000 4
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it's undefined because it's a looping function... for example when you go past 2pi... it repeats over and over, sin(2pi)=sin(4pi)=sin(6pi) , sin(pi)= sin(3pi)=sin(5pi).. etc...
2007-09-01 21:07:47
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answer #6
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answered by driftaddict87 4
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Neither is defined.
2007-09-01 21:21:40
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answer #7
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answered by Anonymous
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undefined
2007-09-05 21:11:11
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answer #8
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answered by z32486 3
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it exists i have found it . it has amazing meaning .
2014-03-24 06:59:31
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answer #9
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answered by oussama 1
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I HAVE NO IDEA
2015-03-20 03:31:03
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answer #10
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answered by Abdo Star 1
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1⤋