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2007-09-01 21:02:12 · 10 answers · asked by Preethikrish 1 in Science & Mathematics Mathematics

10 answers

anything between -1 and 1

2007-09-01 23:59:33 · answer #1 · answered by Mugen is Strong 7 · 0 3

Neither is defined. One may be asked to consider
lim (x->inf)sin x , but that limit does not exists because sin x takes on every value between -1 and 1 as x increases without bound. Same for cos x.

2007-09-02 01:22:18 · answer #2 · answered by Tony 7 · 1 0

It is just a finite value between 1 and -1....but u can't tell the exact value.....whatever u put in sin and cos functions....they just lie from -1 to 1.....infinity may yield anything between them.

2007-09-01 21:25:33 · answer #3 · answered by nik_gupta2006 1 · 1 2

Undefined.

2007-09-01 21:05:02 · answer #4 · answered by symzeiss 1 · 2 0

it could be 1 or -1

2007-09-01 21:11:28 · answer #5 · answered by ptolemy862000 4 · 0 2

it's undefined because it's a looping function... for example when you go past 2pi... it repeats over and over, sin(2pi)=sin(4pi)=sin(6pi) , sin(pi)= sin(3pi)=sin(5pi).. etc...

2007-09-01 21:07:47 · answer #6 · answered by driftaddict87 4 · 0 0

Neither is defined.

2007-09-01 21:21:40 · answer #7 · answered by Anonymous · 1 0

undefined

2007-09-05 21:11:11 · answer #8 · answered by z32486 3 · 0 0

it exists i have found it . it has amazing meaning .

2014-03-24 06:59:31 · answer #9 · answered by oussama 1 · 0 0

I HAVE NO IDEA

2015-03-20 03:31:03 · answer #10 · answered by Abdo Star 1 · 0 1

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