find the length of the diagonal if the length and width are 3 sqrt of 2 and 2 sqrt of 3?sqrt of 5 and 2?

Answer 1

Question 1
d ² = (3√2) ² + (2√3) ²
d ² = 18 + 12
d ² = 30
d = √30

Question 2
d ² = (3√5) ² + 2 ²
d ² = 45 + 4
d ² = 49
d = 7

Answer 2

The assumption that we are making is that you have given the length and width of a rectangle. The second part that you have given is, I assume, what you think the answer should be, but it is wrong.

If it is the diagonal of a rectangle that you have to find, then the diagonal is the hypotenuse of the right angled triangle formed by the sides of the rectangle, and you have to use Pythagoras` Theorem to calculate it.

Pythagoras` Theorem states that in any right angled triangle, the square on the hypotenuse is equal to the sum of the squares on the other two sides. Applying this to the triangle formed, we get:

D^2 = (3rt2)^2 + (2rt3)^2, so

D^2 = 18 + 12, so

D^2 = 30, so

D = rt30 so

D = 5.477. Hope this helps, and sorry to be so long winded about it, but you do seem really confused about it, Twiggy.

Answer 3

Pythagorus

c squared = 18 + 12 = 30
c = sqrt of 30

c squared = 5 + 4 = 9
c = 3

Answer 4

let

a = 3 sqrt (2)
b = 2 sqrt (3)
c = diagonal

using pythagorean's theorem
a^2 + b^2 = c^2

solve for "c"

c = sqrt (a^2 + b^2)
c = sqrt (30)

Answer 5

What polygon is this? And what is "sqrt of 5 and 2"?

Answer 6

do ur home work