Find an expression for the function whose graph is the bottom half of the parabola x+(y-1)^2=0?

Answer 1

x + (y - 1)^2 = 0
(y - 1)^2 = - x
For the bottom half only,
y - 1 = - √(- x)
y = 1 - √(- x), x ≤ 0

Answer 2

while a ingredient is on the x-axis the fee of y is 0. to illustrate if the line intersects the x-axis at -3 then the ingredient is (-3,0). subsequently in the equation: 5x-7y=one 0 five, to detect the x intercept you're making y equivalent to 0. 5x-7(0)=one 0 five 5x=one 0 five x=21 additionally the comparable project with the y by using fact while a ingredient is on the y axis, x is 0. subsequently in the equation: 5x-7y=one 0 five, to detect the y intercept you're making x equivalent to 0. 5(0)-7y=one 0 five -7y=one 0 five y=-15