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-5/3k+2/9=8- -6/5k

2007-09-01 16:51:15 · 7 answers · asked by RedSparkle 1 in Science & Mathematics Mathematics

7 answers

Hi,

If lines are cut off, highlight the ends to see what is missing.

If you really meant to have minus a negative 6/5k, then this is the solution:

To eliminate fractions, multiply by their common denominator of 45 times every term.

-5k.....2.....8....-6k
----..+.--.=.---.-.------
..3......9......1.....5


45(-5k)/3+45(2)/9.=.45(8).-45(-6k)/5

15(-5k).+.5(2).=.45(8).-.9(-6k)

-75k.+.10.=.360..+.54k
-75k.=.350..+.54k
-129k.=.350
k = -350/129 <== answer if - -6/5k was correct

However, that answer was so ugly, I thought maybe the problem was supposed to be:

-5k.....2.....8.....6k
----..+.--.=.---.-.------
..3......9......1.....5

Multiply every term by the LCD of 45 to eliminate fractions.

45(-5k)/3+45(2)/9.=.45(8).-.45(6k)/5

15(-5k).+.5(2).=.45(8).-.9(6k)

-75k.+.10.=.360.-.54k

-21k = 350

k = -50/3 <== answer if - 6/5k was correct

This seems a little more normal as an answer.

I hope that helps!! :-)

2007-09-01 17:16:20 · answer #1 · answered by Pi R Squared 7 · 0 0

- 5/3k + 2/9 = 8 - (- 6/5k)
- 5/3k + 2/9 = 8 + 6/5k
2/9 - 8 = 6/5k + 5/3k
- 7 7/9 = 18/15k + 25/15k
- 7 7/9 = 43/15k
k = (- 7 7/9) / 43/15
k = - 70/9 * 15/43
k = - 350/129
k = - 2 92/129

2007-09-04 23:45:30 · answer #2 · answered by Jun Agruda 7 · 3 0

-5/3 k + 2/9 = 8 - (-6/5k)

2/9 - 8 = 6/5 k + 5/3 k

2-72 / 9 = 18+25 / 15 k

-70/9 = 43/15 k

k = -70/9 x 15/43

k = -350/129 or -2.7132 (4 d.p)

2007-09-01 17:02:34 · answer #3 · answered by happynanny03 1 · 0 0

-(5/3)k + 2/9 = 8 - (6/5)k

Multiply both sides by the LCD, 45

- 75k + 10 = 360 - 54k

- 21k = 350

k = - 16 2/3

2007-09-01 17:05:32 · answer #4 · answered by Anonymous · 0 0

the lcm of 3,9, and 5 is 45
So multiply the eq by 45

-75k +10 = 360 - (-54)k
-129k = 350
k = - 350/129

2007-09-01 17:00:56 · answer #5 · answered by norman 7 · 0 0

(x - 8)(x - ok) = x^2 - 5kx + m ax^2 + bx + c = 0 a = a million b = -5k c = m (x - 8)(x - ok) x^2 - kx - 8x + 8k a = a million b = -ok - 8 c = 8k -5k = -ok - 8 -4k = -8 ok = 2 8k = m 8 * 2 = m sixteen = m B) sixteen (x - 8)(x - 2) = x^2 - 5 * 2x + sixteen x^2 - 2x - 8x + sixteen = x^2 - 10x + sixteen x^2 - 10x + sixteen = x^2 - 10x + sixteen

2016-12-16 09:02:28 · answer #6 · answered by Anonymous · 0 0

Isolate the k and simplify.

2007-09-01 16:57:01 · answer #7 · answered by Matiego 3 · 1 0

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