x+y = 2
then y = 2-x
2x-y=1
then y = 2x-1
graph two equation and youwill see the intersection at
x= 1, y =1
2007-09-01 16:04:46
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answer #1
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answered by Helper 6
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You can solve this either by substitution or elimination.
By substitution, you need to express one equation as y = something or x = something and then substitute it into the other equation. By inspection, it is easier to do y = something because the other equation contain just 1y or y only.
so the first equation is y = 2-x, subs to 2x -y = 1 becomes 2x - (2-x) = 1 or 2x -2 +1x = 1
or, 3x -2 = 1
3x = 1 + 2
3x = 3
therefore, x = 1
to find the y value just substitute into either equation. But sometimes it is important to check which one is easier to evaluate. In this case, it is the first one. 1 + y = 2, or y = 2 -1 or y = 1
In elimination, you line up your equations, like so,
x + y = 2
2x - y = 1 , note by adding, you eliminate y
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3x = 3
x = 1, etc to get y =1
Thus the point of intersection, is (1,1)
You can also graph the equations before or after solving algebraically.
2007-09-01 16:15:13
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answer #2
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answered by Aldo 5
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x + y = 2
2x - y = 1--------ADD
3x = 3
x = 1
y = 1
Point of intersection is (1 , 1)
2007-09-05 10:33:37
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answer #3
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answered by Como 7
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im thinking .3333 repeating and 1.6 repeating i hope i did that right
2007-09-01 16:05:48
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answer #4
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answered by Tay M 2
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