ur school is 18 3/4 miles south of pittsburgh and ur house is 44 1/4 miles south of pittsburgh. u leave ur school at 5:00 pm, traveling south by bicycle at an average speed of 15 miles per hour. ur father leaves pittsburgh in a car at 5:45 PM. He is driving south at an average speed of 55 miles per hour. let 't' represent the time it takes ur father to drive from pittsburgh toward ur house.
3. write an equation to find ur distance 'd1' from pittsburgh after 't' hours. the answer is d1=18 3/4 + 15(t +3/4)
4.write an equation to find ur father's distance 'd2' from pittsburgh after 't' hours. the answer is: d2=55t
5. use ur equations from exercises 3 and 4 to find how long it takes ur father to pass you
is the answer an hour and 33 minutes?
and how do i get the answer to this question
6. find the number of hours you rode your bicycle when your father passes you.
2007-09-01 15:02:32 · 2 answers · asked by Kendra C 2 in Science & Mathematics ➔ Mathematics
5. Your father passes you when d1 and d2 equal to each other.
d1 = d2
18.75 + 15(t + 0.75) = 55t
18.75 + 15t + 11.25 = 55t
7.5 = 40t
t = 0.1875 hours, which is 11.25 minutes and represents the time 5:56 pm and 15 seconds.
6. Since you started riding at 5pm and your father started driving at 5:45 pm, you rode for 45 minutes, or 0.75 hours, longer than he drove. Your riding time was therefore 0.75 + 0.1875 = 0.9375 hours.
2007-09-05 05:16:14 · answer #1 · answered by DavidK93 7 · 0⤊ 0⤋
In using equations 3 and 4, keep in mind that that the t found is the time that the FATHER started his ride.
So you can set equations 3 and 4 together, and the time seems about right in terms of when the STUDENT started his bicycle ride.
Since you set the equations this way, this is also the answer to problem 6.
2007-09-01 22:18:32 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋