someone please help me with this one.
an insect crawls along the edge of a rectangular swimming pool of length 27 m and width 21m. if it crawls from corner A to corner B in 30 min. What is magnitude of its average velocity?
2007-09-01 13:12:59 · 2 answers · asked by Adse P 1 in Science & Mathematics ➔ Physics
Assuming corners A and B are diagonally opposite, then the insect crawled 48 meters (27 m + 21 m) in 30 minutes. So it's average velocity would be 96 m/hour (48 * 2) or 1.6 m/minute (48/30).
2007-09-01 13:27:07 · answer #1 · answered by Shev 3 · 0⤊ 0⤋
Velocity is a vector quantity, it has magnitude and direction.
Average velocity is total displacement divided by total time.
Resultant displacement(total displacement):
√(27^2 + 21^2) = 34.205meters
v = D/t = 34.205/30 =1.14meters/minute
1.14/60 = 0.019m/s
2007-09-01 13:24:39 · answer #2 · answered by jsardi56 7 · 0⤊ 0⤋