2x^2 - 4x +1 = 0
could you show how this problem is done also
2007-09-01 12:17:09 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Sarah: divide the equation by 2
x^2 - 2x + 1/2 = 0
completing the square you get,
x^2 - 2x + 1 + 1/2 -1 = 0 (add 1 and subtract 1)
(x-1)^2 = 1/2
taking the square root on both sides of the equation you get
x-1 = +/- sqrt(1/2)
x = 1-sqrt(1/2); 1+sqrt(1/2)
hope this explanation helps!
2007-09-01 12:25:04 · answer #1 · answered by alrivera_1 4 · 0⤊ 3⤋
Using the quadratic formula
x = [ -b +/- sqrt (b^2 - 4ac)] / 2a
a = 2
b = -4
c = 1
x = [ -(-4) +/- sqrt ((-4)^2 - 4(2)(1)) ] / 2(2)
x = [ 4 +/- sqrt (8) ] / 4
x = [4 +/- 2sqrt 2] / 4
x = 2[2 +/- sqrt2] / 2(2)
x = [2 +/- sqrt2] / 2
either x = [2 + sqrt2] / 2
x = 1.707
or x = [2 - sqrt2] / 2
x = 0.293
2007-09-01 12:47:47 · answer #2 · answered by afriprince2 2 · 0⤊ 0⤋
2x^2 - 4x +1 = 0
(2x-1)^2 = 0
2x-1 = 0
2x=1
x=1/2 <-- this is a double root
2007-09-01 12:31:12 · answer #3 · answered by ironduke8159 7 · 1⤊ 0⤋
(2x-1)(2x-1)=0
x = 1/2
2007-09-01 12:23:14 · answer #4 · answered by chasrmck 6 · 1⤊ 0⤋