factor this 2x^2-x-3 and this 5x^2+34x-7
both are 2 different questions
2007-09-01 11:57:05 · 5 answers · asked by mercedes'08 1 in Science & Mathematics ➔ Mathematics
2x^2 - x - 3
(2x - 3)(x + 1)
2x - 3 = 0
2x = 3
x = 3/2
x + 1 = 0
x = -1
5x^2 + 34x - 7
(5x - 1)(x + 7)
5x - 1 = 0
5x = 1
x = 1/5
x + 7 = 0
x = -7
just plug all the answers into the original equations to make sure they all check out. discard any answers that don't.
2007-09-01 12:47:19 · answer #1 · answered by peachi517 2 · 0⤊ 0⤋
2x^2-x-3 = (2x - 3)(x +1)
5x^2+34x-7 = (5x -1)(x + 7)
2007-09-01 19:08:01 · answer #2 · answered by Beardo 7 · 0⤊ 0⤋
(2x -3)(x+1) = 2x^2 -x -3
(5x -1)(x+7) = 5x^2 +34x -7
2007-09-01 19:05:53 · answer #3 · answered by skipper 7 · 0⤊ 0⤋
(2x-3)(x+1) and(5x-1 )(x + 7)
2007-09-01 19:03:37 · answer #4 · answered by chasrmck 6 · 0⤊ 0⤋
1st . (2x-3)(x+1)
2nd. (5x-1)(x+7)
2007-09-01 19:04:05 · answer #5 · answered by Arif Sanchez 1 · 0⤊ 0⤋