Divide and simplify. Assume no denominator has a 0 value.
x^2-5x+6/x+5 divided by x+1/x+5
2007-09-01 11:53:13 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
(x - 3) (x - 2) / (x + 1) is answer.
2007-09-05 08:32:16 · answer #1 · answered by Como 7 · 0⤊ 0⤋
x^2-5x+6 / x+5 divided by x+1 / x+5
Consider x^2-5x+6
x^2-5x+6
= x^2 - 2x - 3x +6
= x(x-2) -3(x-2)
=(x-2)(x-3)
So x^2-5x+6 / x+5 divided by x+1 / x+5
= (x-2)(x-3) / x+5 divided by x+1 / x+5
= (x-2)(x-3) / x+5 multiplied by x+5 / x+1
= (x-2)(x-3)(x+5) / (x+5)(x+1)
= (x-2)(x-3) / x+1
2007-09-01 19:06:47 · answer #2 · answered by afriprince2 2 · 0⤊ 0⤋
That's easy:
the x+5 in the denominators cancel each other so you are left only with:
x^2-5x+6 / x+1
Now the enumerator can be factored to (x-3)(x-2) so I guess the answer is:
(x-3)(x-2) / (x+1)
2007-09-01 19:13:00 · answer #3 · answered by Shai 2 · 0⤊ 0⤋
=[(x-3)(x-2)/(x+5)][(x+5)/(x+1)]
= (x-3)(x-2)/(x+1)
2007-09-01 19:04:54 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
answer: X^2-4X+5
2007-09-01 18:59:17 · answer #5 · answered by Anonymous · 0⤊ 0⤋