One day, the temperature at 2:00 A.M. was 43°F, and by 3:00 P.M. the temperature was 56°F. What was the hourly rate of temperature change? I got 2f/h, but I do not feel this is correct....anyone confirm? Show me what I am doing wrong?
And this one i sBUGGING ME as well!
Find two consecutive integers such that the sum of 2 times the first integer and 7 times second integer is 88.
2007-09-01 11:51:59 · 7 answers · asked by ? 1 in Science & Mathematics ➔ Mathematics
1) 2 AM to 3 PM is 13 hours
56 deg - 43 deg = 13 deg
So, the hourly rate of temp change is 1 degree per hour
2) Let n = the first integer and
let n+1 = the second integer
2n + 7(n+1) = 88;
2n + 7n + 7 = 88;
9n + 7 = 88;
9n = 81
n=9 and n+1 = 10
2007-09-01 12:07:47 · answer #1 · answered by snore25 3 · 0⤊ 0⤋
why is it 2 f/h?
The raise in temp is 56 - 43 = 13.
The number of hours between 2am and 3pm is 13
Rate = temp/hour = 13/13 = 1 f/h
Let n be the small # then (n+1) is the next consecutive #
2n + 7(n+1) = 88
9n + 7 = 88
9n = 81
n = 9
the # are 9 and 10
check 2 * 9 +7 * 10 = 88
2007-09-01 19:04:53 · answer #2 · answered by norman 7 · 0⤊ 0⤋
56 -43 = 13
3pm - 2am = 13 hours
so the change per hour = 13/13 = 1 degree /hour
2x + 7(x+1) = 88 = 9x +7
9x = 81
9 and 10
2007-09-01 19:01:45 · answer #3 · answered by Beardo 7 · 0⤊ 0⤋
Temp change = 13 deg
Time change = 13 hours
So hourly rate = 1 deg/hour
2007-09-01 19:01:52 · answer #4 · answered by Anonymous · 0⤊ 0⤋
i think the temperature goes up one degree each hour because 13 hours pass from 2:00A.M. to 3:00P.M. and the temp. raises 13 degrees in that time so it goes up one degree each hour
and sorry as for the second one i 4got how to do those i havent been back 2 school yet
2007-09-01 19:06:31 · answer #5 · answered by demon3275 1 · 0⤊ 0⤋
= (56 - 43) / (15 - 2)
= 13 / 13
= 1F/h
Answer: 1 degree Fahrenheit per hour
2007-09-05 04:43:49 · answer #6 · answered by Jun Agruda 7 · 3⤊ 0⤋
easy, in 13 hrs the temp rose 13 deg, so rate = 1 deg per hr
2007-09-01 19:00:55 · answer #7 · answered by stagger3 2 · 0⤊ 0⤋