2007-09-01 11:01:24 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
b (a + 3) = 3 a + 2
b a + 3 b = 3 a + 2
(b - 3) a = 2 - 3 b
a = (2 - 3 b) / (b - 3)
2007-09-05 08:26:51 · answer #1 · answered by Como 7 · 0⤊ 0⤋
b = (3a + 2) / (a + 3)
b (a + 3) = 3a + 2
ab + 3b = 3a + 2
ab + 3b -3a = 2
ab - 3a = 2 - 3b
a(b - 3) = 2 - 3b
a = (2 - 3b) / (b - 3)
2007-09-01 18:15:11 · answer #2 · answered by afriprince2 2 · 0⤊ 0⤋
a = [(2-3b)/(b-3)]
2007-09-01 18:08:15 · answer #3 · answered by frisbers 1 · 0⤊ 0⤋
b=(3a+2)/(a+3)
ab+3b=3a+2
ba-3a=2-3b
a(b-3)=2-3b
a=(2-3b)/)b-3).ANS.
2007-09-01 18:08:27 · answer #4 · answered by Anonymous · 0⤊ 0⤋