how do you solve the equation?

0 ⤊

solve the following equation by using the quadratic formula.

y^2-6y+11=0

2007-09-01 10:45:48 · 3 answers · asked by What's up people!! 1 in Science & Mathematics ➔ Mathematics

y = ( 6 +- sqrt( 36 - 44) )/ 2 since 36-44 <0 this equation has NO solutions.

2007-09-05 05:21:21 · answer #1 · answered by georgina 6 · 0⤊ 0⤋

Have you learned i = ï sqrt(-1)?
y = (6 +- sqrt(36-44))/2
= 3 +- sqrt(-2)
= 3 +- i sqrt(2)

2007-09-01 10:56:12 · answer #2 · answered by Hahaha 7 · 0⤊ 0⤋

yÂ²-6y+11=0
(y-5)(y-6)=0
y=5,6

Coordinate:
(5,6)(6,11)

2007-09-01 11:01:31 · answer #3 · answered by Anonymous · 0⤊ 1⤋