3p - 1 = 5p - 5 - 14 + 4p
3p - 1 = 9p - 19
18 = 6p
p = 3
2007-09-05 08:45:18
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answer #1
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answered by Como 7
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3p - 1 = 5(p-1) - 2(7-2p)
Distribute the multiplications...
3p - 1 = 5p - 5 - 14 + 4p
Simplify each side...
3p - 1 = 9p - 19
Subtract 9p and add 1 for both sides...
-6p = -18
Divide both sides by -6...
p = 3
2007-09-01 17:48:13
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answer #2
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answered by richarduie 6
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p=3
2007-09-01 17:47:59
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answer #3
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answered by la la la la 3
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p=3
2007-09-01 17:44:36
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answer #4
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answered by frisbers 1
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3p-1=5(p-1)-2(7-2p)'
3p-1=5p-5-14+4p
3p-5p-4p=-5-14+1
-6p=-18
p=3 AN.S.
2007-09-01 17:46:03
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answer #5
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answered by Anonymous
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3p - 1 = 5(p-1) - 2(7-2p)
3p-1=5p-5 -14+4p
3p - 5p -4p = -5-14+1
-6p = -18
p =3
2007-09-01 17:45:52
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answer #6
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answered by ironduke8159 7
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Hi
3p -1 = 5p - 5 -14 + 4p
3p -1 = 9p - 19
-6p = -18
6p = 18
p = 3
Do you know how this is done? First you simplify, then you put the p and the numbers on opposite sides.
Hope this helped :-)
2007-09-01 17:44:15
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answer #7
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answered by F 6
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3p -1 = 5p -5 - 14 + 4p^2
4p^2 + 2p - 18 = 0
2p^2 + p - 9 = 0 .. solving
p = -2.386 . . . and . . . 1.886
OK . . .. i got it wrong
its the p^2
2007-09-01 17:42:57
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answer #8
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answered by CPUcate 6
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