f(x)=2√x+3
g(x)=-3x+1
Does f(g(1))=2? That's what I got, but I'm not sure I did it right.
2007-09-01 09:56:13 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
There is a negative in front of the 3x
2007-09-01 10:07:14 · update #1
2√(x+3)
Also, what would you do with 2√-8? That's not a number.
2007-09-01 10:17:01 · update #2
f(x)=2√x+3
g(x)=-3x+1
f(g(x)) = 2√(-3x+1)+3
f(g(1)) = 2√(-3*1) +3 = 2sqrt(2)i +3
But if you meant f(x) = √(x+3), then
g(1) = -2, and so
f(-2) = 2sqrt(-2+1) = 2
Please be careful to indicate what is all under the √ sign by appropriate use of parentheses.
2007-09-01 10:10:57 · answer #1 · answered by ironduke8159 7 · 1⤊ 0⤋
I do see a minus in front of the 3x+1
g(1)=-3+1= -2
f(-2)=2â-2 +3 = 2â2i +3
2007-09-01 17:02:01 · answer #2 · answered by chasrmck 6 · 1⤊ 0⤋
f(x)=2âx+3
g(x)=-3x+1
g(1) = -3 * 1 +1 = -3 + 1 = -2
f(g(1)) = f(-2) = 2â(-2+3) = 2 â1 = 2
2007-09-01 17:20:00 · answer #3 · answered by GPC 3 · 1⤊ 0⤋
fg(1) = f(3(1)+1) = f(4) = 2sqrt(4)+3 = 7
2007-09-01 17:01:59 · answer #4 · answered by holdm 7 · 0⤊ 1⤋
g(1)=4
f(4)=7
f(g(1))=7
2007-09-01 17:01:27 · answer #5 · answered by eremieb 2 · 0⤊ 1⤋