Factor completely: 25x^2 -y^4?

2 ⤊

Factor completely: 25x^2 -y^4?

2007-09-01 09:28:48 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

4 answers

25x^2-y^4
5^2 x^2 -(y^2)^2
(5x)^2 -(y^2)^2
(5x -y^2)(5x+y^2)

2007-09-01 09:36:33 · answer #1 · answered by Helper 6 · 0⤊ 2⤋

Let's factor out a negative sign first

25x^2 - y^4 = -(-25x^2 + y^4)

so you end up with

-(y^4 - 25x^2)

Does this look familiar? Remember a^2 - b^2 = (a+b)(a-b)

a=y^2
b=5x

-(y^2 + 5x) (y^2 - 5x)

2007-09-01 16:35:48 · answer #2 · answered by Vu 3 · 0⤊ 0⤋

25x^2 -y^4=(5x-y^2)(5x+y^2)

2007-09-01 16:35:02 · answer #3 · answered by Anonymous · 0⤊ 0⤋

( 5 x - y Â² ) ( 5 x + y Â² )

2007-09-05 11:58:13 · answer #4 · answered by Como 7 · 2⤊ 0⤋