chemistry help?

Question

1.how many moles of water can be made from 4 moles of oxygen gas and 16 moles of hydrogen gas? what is the limiting reagent?

2. what is the mass of water produced from the reaction of 24g of H2 and 160 g of O2. what is the limiting reagent?

Answer 1

1. 8 moles of water . The limiting reagent is oxygen.

4O2 + 8H2 = 8H2O

NB the starting amount is 16H2 but only 8H2 is used leaving 8H2 unused. Hydrogen in excess so oxygen is limiting reagent.

2. Mass produced is 180g.
Moles of (H2) = 24g/2 = 12 mol(H2)
moles of (O2) = 160g.32 = 5 mol(O2)
10H2 + 5O2 = 10H2O
mass/g(H2O) = 10 moles x 18 (Mr water)
mass/g(H2O) = 180g

NB Hydrogen is two moles in excess. So oxygen is the limiting reagent.

Answer 2

My guess.1. 4, neither. 2. 10, oxygen