2007-09-01 09:21:02 · 6 answers · asked by NERD 1 in Science & Mathematics ➔ Chemistry
Pb(BrO2)2
2007-09-01 09:29:18 · answer #1 · answered by lenpol7 7 · 0⤊ 0⤋
You want to look at the parenthetical Roman number in the written name to obtain the charge for the lead ion present in this compound. This number is II (2) therefore, lead is present as Pb^2+. You will need to look up the bromite ion in a table of polyatomic ions, and you will find that it is BrO2^-. From here, you just put this together as you would with a simple ionic compound. The result will be:
Pb(BrO2)2
What this is telling you is that you need one Pb ion and 2 bromite ions to balance the charge. You must put the parentheses around the bromite ion to indicate that it is the entire polyatomic ion that we need two of, not just a particular atom within the ion.
As a side note, some of the other answers are saying PbBr2. This is known as Lead (II) Bromide, not Lead (II) Bromite.
When you see the suffix "ite" or "ate" on a name, recognize that it is likely a polyatomic ion.
2007-09-01 09:31:02 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Pb(BrO2)2.
It is similar to the naming of the chloride salts. Hypochlorite is ClO, Chlorite is ClO2, Chlorate is ClO3.
2007-09-01 12:42:38 · answer #3 · answered by scott k 4 · 0⤊ 0⤋
Usually written as PbBr2.
2007-09-01 09:26:33 · answer #4 · answered by Anonymous · 0⤊ 0⤋
PbBr2
2007-09-01 09:28:16 · answer #5 · answered by Anonymous · 0⤊ 0⤋
Aluminium Sulfide- Al(SUB)2(/SUB)S(SUB)3(/SUB) Carbon Disulfide - CS(SUB)2(/SUB)
2016-05-18 22:52:23 · answer #6 · answered by ? 3 · 0⤊ 0⤋