can u tell me how to factor
2x^3+6x^2+3x+9 by grouping?
2007-09-01 09:15:04 · 4 answers · asked by mercedes'08 1 in Science & Mathematics ➔ Mathematics
2x^3+6x^2+3x+9
=2x^2(x+3) + 3(x+3)
=(2x^2+3)(x+3)
2007-09-01 09:25:27 · answer #1 · answered by ironduke8159 7 · 0⤊ 0⤋
Factor the 2x^2 from the first two terms:
2x^2(x + 3) and 3 from the next two:
3(x +3). So now you have an x+3 you can factor out of the two terms you have:
(x+3)(2x^2 +3)
Which is about as far as you can go.
2007-09-01 16:29:20 · answer #2 · answered by rrsvvc 4 · 0⤊ 0⤋
2x³+6x²+3x+9
it is already grouped for you so just:
2x²(x+3) + 3(x+3)
collecting common terms again to get:
(2x²+3)(x+3)
2007-09-01 16:27:01 · answer #3 · answered by 037 G 6 · 0⤊ 0⤋
2x^3+6x^2+3x+9=(2x^3+6x^2)+(3x+9)
=2x^2(x+3)+3(x+3)
=(x+3)(2x^2+3)
2007-09-01 16:29:43 · answer #4 · answered by Anonymous · 0⤊ 0⤋