2007-09-01 08:07:06 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Add 7 on both sides,
|x-6| ≥ 6, which is equivalent to
x-6 ≤ -6 or 6 ≤ x-6
Therefore, the solution is
x ≤ 0 or x ≥ 12
2007-09-01 08:16:14 · answer #1 · answered by sahsjing 7 · 0⤊ 0⤋
No it = +1
2007-09-01 08:16:17 · answer #2 · answered by Gordon R 3 · 0⤊ 0⤋
what's x?
if you're looking for x:
|x-6| -7 >/= (greater or equal to) -1
|x-6| >/= -1 + 7
|x-6|>/= 6
x can't be 1 - 12 (look at it to figure this out)
(note, those bars around x-6 mean that you take the positive answer
ex. 1-6 = -5
but |1 - 6| = 5
we call this the magnitude of a number
ex.1 - 6= 5
but the magnitude of 1 -6 = 5
and therefore, the domain of x (the numbers that x can be)
are 11< x<1
meaning that x has to be larger than 11, and less than 1 for this inequality to be true.
0 >/= x>/= 12 is the same thing.
2007-09-01 08:16:43 · answer #3 · answered by (+_+) B 4 · 0⤊ 0⤋
|x-6|-7 >= -1
|x-6| >= 6
x>=12 or x >=0
2007-09-01 08:40:38 · answer #4 · answered by ironduke8159 7 · 0⤊ 0⤋
|x-6|-7 ⥠-1
|x-6| â¥7 -1
|x-6| ⥠6
x-6 ⤠-6 or 6 ⤠x-6
x ⤠0 or x ⥠12
2007-09-01 08:17:16 · answer #5 · answered by harry m 6 · 0⤊ 0⤋
x has to be less than or equal to zero
or
x has to be greater than or equal to 12
2007-09-01 08:22:02 · answer #6 · answered by zanthus 5 · 0⤊ 0⤋
I don't know, is it?
Do your own bloody homework. Or at least ask properly if you need help.
2007-09-01 08:10:57 · answer #7 · answered by Anonymous · 1⤊ 0⤋
|x-6|-7>_-1
x-6>_6
x>_12
2007-09-01 08:22:45 · answer #8 · answered by peter d 2 · 0⤊ 0⤋
No dont now
2007-09-01 10:43:55 · answer #9 · answered by Anonymous · 0⤊ 0⤋