I can't get it...
2x^2 - 5x - 3
2007-09-01 06:47:59 · 7 answers · asked by lost.in.love 4 in Science & Mathematics ➔ Mathematics
(2x + 1) (x - 3)
2007-09-01 08:05:31 · answer #1 · answered by Como 7 · 1⤊ 0⤋
2x² - 5x - 3 = 0
The middle term is - 5x
Find the sum of the middle term
Multiply the first term 2 times the last term 3 equals 6 and factor
factors of 6
1 x 6. . .â. .use these factors
2 x 3
+ 1 and - 6 satisfy the sum of the middle term
insert + 1x and - 6x into the equation
2x² - 5x - 3 = 0
2x² + 1x - 6x - 3 = 0
Group factor
(2x² + 1x) - (6x - 3) = 0
When a negative symbol (-) precedes a parenthesis and the parenthesis are remoed the signs changes from negative ( - ) to positive( + )
x(2x + 1) - 3(2x + 1) = 0
(x - 3)(2x + 1) = 0
- - - - - - - s-
2007-09-01 14:46:47 · answer #2 · answered by SAMUEL D 7 · 1⤊ 0⤋
(2x + 1)(x -3) Checking by multiplying and showing all terms is: 2x^2 + x - 6x -3. Simplifying by adding like terms: 2x^2 - 5x - 3. There's your answer.
2007-09-01 14:04:15 · answer #3 · answered by Emissary 6 · 0⤊ 0⤋
2x^2 - 5x - 3
= (2x+1)(x-3)
--------
Ideas: 2(-3) = 1(-6) and 1-6 = -5, the coefficient of the linear term.Therefore 2x(-3) + x(1) = -5x.
2007-09-01 13:59:08 · answer #4 · answered by sahsjing 7 · 0⤊ 0⤋
2x^2-5x-3
=2x^2-6x+x-3
=2x(x-3)+1(x-3).
=(x-3)(2x+1)/ ANS.
2007-09-01 13:56:30 · answer #5 · answered by Anonymous · 0⤊ 0⤋
(x-1 ) (2x-3 ) = 2x^2 -5x +3
2007-09-01 13:59:57 · answer #6 · answered by charliefromwashington 3 · 0⤊ 0⤋
(x-3)(2x+1)
2007-09-01 13:54:24 · answer #7 · answered by ? 3 · 0⤊ 0⤋