sint(t)=1/7
Using pythagorean theorm, cost(t) should equal: -(48^.5)/7
RIGHT????
2007-09-01 06:25:05 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
cost(t) is less than 0
2007-09-01 06:38:10 · update #1
bashah1939 doesnt understand when i say cos(t)<0
2007-09-09 03:58:19 · update #2
sin t = y / r = 1 / 7
cos t = x / r
r ² = x ² + y ²
x ² = 7 ² - 1 ²
x ² = 48
x = √48
cos t = ( √48 ) / 7 = 4√3 / 7
2007-09-05 08:02:06 · answer #1 · answered by Como 7 · 2⤊ 0⤋
Yes.
sin t = 1/7
Where 180° < t < 90°
Since: sin² t + cos² t = 1
Then:
cos² t = 1 - sin² t
cos² t = 1 - (1/7)²
cos² t = 1 - 1/49
cos² t = (49 - 1) / 49
cos² t = 48 / 49
cos t = - √(48 / 49), because cos t<0 when 180° < t < 90°
cos t = - √48 / 7
Bye, bye and Good Luck !!
>(^_ ^)<
2007-09-01 06:29:17 · answer #2 · answered by Anonymous · 0⤊ 1⤋
once you have a 30-60-ninety triangle, the lengths are continuously interior the ratio of x : x?3 : 2x. this could be a competent element to memorize. enable's say the long leg of the triangle is 50 gadgets. this means the quick leg is 50 / ?3, and the hypotenuse is two(50 / ?3), or 2(50?3 / 3) = one hundred?3 / 3
2016-11-13 22:19:27 · answer #3 · answered by kennebeck 4 · 0⤊ 0⤋
nooo
it is root 48 / 7 not negative root
just 48^0.5 / 7
2007-09-01 06:29:28 · answer #4 · answered by emy 3 · 0⤊ 1⤋
Answer = (48^.5)/7 . YOUR ANSWER IS WRONG BECAUSE IT HAS A MINUS SIGN BEFORE IT.
2007-09-08 23:32:16 · answer #5 · answered by bashah1939 4 · 0⤊ 1⤋
you may want to get rid of the minus sign.
2007-09-08 14:36:30 · answer #6 · answered by Anonymous · 0⤊ 0⤋
you are right. It can be further simplified
-sqrt(48)/7 = -sqrt(16*3)/7
= -4/7[sqrt(3)]
2007-09-01 07:18:30 · answer #7 · answered by mohanrao d 7 · 0⤊ 2⤋
sin(t)=1/7
7^2=(x^2)+(1^2)
x^2=49-1=48
x=48^.5
hence
cos(t)=(48^.5)/7
2007-09-07 14:44:20 · answer #8 · answered by tarek n 1 · 0⤊ 1⤋
Yes, if t is in the second quadrant.
2007-09-01 06:31:49 · answer #9 · answered by sahsjing 7 · 1⤊ 0⤋