Well, it is pretty hard to type here. I'll put it in words. Hope you get it.
Left hand side (LHS) of the equation:
x to the power √x³ to the power ³√x
Right Hand Side (RHS) of the equation:
(x√x)^(x)
Now, find the sum of the positive roots of the equation.
2007-09-01 01:34:35 · 7 answers · asked by Akilesh - Internet Undertaker 7 in Science & Mathematics ➔ Mathematics
Left hand side (LHS) of the equation:
x to the power √x³ to the power ³√x
=x^√x³ ^³√x
Rule a^m^n = a^mn
=x^√x³ ^³√x
= x^(x^3/2)×x^(1/3)
= x^(x^(3/2 + 1/2)
= x^x^(11/6)
Right Hand Side (RHS) of the equation:
(x√x)^(x)
= [x^1 × x^1/2]^x
= [x^(1+ 1/2)]^x
= x^3x/2
Equating both sides
x^x^(11/6) = x^x^3x/2
Therefore comparing index,
x^(11/6) = x^3x/2
11/6 = 3x/2
x = 11× 2/ 6 × 3
or x = 11/9
2007-09-02 05:09:45 · answer #1 · answered by Pranil 7 · 0⤊ 0⤋
Suppose x to the power of 'a' to the power of 'b' = x to the power of 3/2 to the power of x.
Taking log on both sides
log (x to the power of 'a' to the power of 'b') = log (x to the power of 3/2 to the power of x)
a b logx = 3/2 x logx
(a b)/x = 3/2
2007-09-01 10:20:57 · answer #2 · answered by pereira a 3 · 0⤊ 0⤋
I hated math in school for these very problems.
2007-09-01 08:44:17 · answer #3 · answered by Anonymous · 0⤊ 2⤋
i donot understand what do u want to say
2007-09-02 09:00:00 · answer #4 · answered by abhishekkharbanda_abhi 2 · 0⤊ 0⤋
i solved it its come 0
but cant write the whole long solution here.
2007-09-01 09:16:50 · answer #5 · answered by mariumgl 2 · 0⤊ 1⤋
is tat ur assignment
2007-09-01 09:05:49 · answer #6 · answered by preeeeeeee 2 · 0⤊ 2⤋
So sory its difficult 2 understand wat u wanna say
2007-09-01 08:45:58 · answer #7 · answered by SwEEEt 1 · 0⤊ 2⤋