29-{5+3[8.(10-8)]-50}
now the period is suppose to be a dot in the middle. i couldn't find a key to properly put that, and I know I need to multiply that.
2007-08-31 19:39:59 · 5 answers · asked by msdood1 4 in Science & Mathematics ➔ Mathematics
29-{5+3[8*(2)]-50} =
29-{5+3[16]-50}=
29-{5+48-50}=
29-{53-50}=
29-3 =
26 is your answer.
good luck
2007-08-31 19:45:03 · answer #1 · answered by gibsongtar101 3 · 0⤊ 0⤋
29 - [ 5 + 3 (16) - 50) ]
29 - [ 5 + 48 - 50 ]
29 - [ 3 ]
26
2007-09-01 03:20:10 · answer #2 · answered by Como 7 · 0⤊ 0⤋
first 10-8 = 2
then 2 times the 8 = 16
next 16 times 3 = 48
5+48-50=3
29-3=26
order of operations
1 do what ever is in the parenthesis starting with the deepest level
2 order of operations
multiplication & division.
last addition & subtraction
2007-09-01 02:49:23 · answer #3 · answered by 037 G 6 · 0⤊ 0⤋
29-[5+3(8*2)-50]
=29-[5+48-50]
=29-(53-50)
=29-3
=26
hope this helps
2007-09-01 02:46:03 · answer #4 · answered by Ryan J 2 · 0⤊ 0⤋
=29-{5+3[8.(10-8)]-50}
=29-{5+3[8.2]-50}
=29-{5+24.6-50}
=29-20.4
=8.6
2007-09-01 02:53:24 · answer #5 · answered by Jun Agruda 7 · 3⤊ 0⤋