what is the mass of oxygen produced from the decomposition of 75 grams of potassium chlorate?
2KClO3 --> 2KCl + 3O2
thanks in advance
2007-08-31 19:34:31 · 3 answers · asked by Tammy 2 in Science & Mathematics ➔ Chemistry
n(KCL)=m(KCL)/M(KCL)= 75/74.5= 1.01(mol)
The number of mol of oxygen: 1.01/2=0.51(mol)
Mass of oxygen: m(O2)= n(O2)*M(O2)=0.51*32=16.32(g)
2007-08-31 19:47:05 · answer #1 · answered by english_improve 3 · 0⤊ 0⤋
Molar mass of KClO3 = 39+35.5+48 = 122.5 g
Now use Mole concept.
2007-09-01 02:42:25 · answer #2 · answered by ag_iitkgp 7 · 1⤊ 0⤋
given: 75g of KClO3
I'm going to call KClO3 "A" and O2 "B" for ease of typing.
(75gA)(1molA/122.5gA)(3molB/2molA)(32gB/1molB)
all units except grams of B (which I defined as O2) cancel.
=29.388g O2 or 29gO2 to sig figs.
hope this helps
2007-09-01 03:14:07 · answer #3 · answered by Ryan J 2 · 1⤊ 0⤋