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this ia a question related with 3-D and vectors.

2007-08-31 16:55:54 · 9 answers · asked by Vrun S 1 in Science & Mathematics Mathematics

9 answers

3 non collinear points determine a plane. If you have 4 non coplaner points, you need to select 3 of these. This can be calculated by using combination. Hence 4C3 = (4 x 3 x 2) / (3 x 2 x 1) = 4. This problem is not related to vectors, as planes have no directions. A plane is a set of points on a flat surface extending in all directions. ( e.g. surface of a table expanding in all directions)

2007-08-31 20:36:55 · answer #1 · answered by pereira a 3 · 0 0

Coplanar Planes

2016-10-18 08:55:09 · answer #2 · answered by ? 4 · 0 0

4

2007-08-31 17:03:07 · answer #3 · answered by Anonymous · 0 0

3 points are always coplanar so from 4 non coplanar points, the number of planes formed
= C(4, 3)
= 4

2007-08-31 17:17:00 · answer #4 · answered by sv 7 · 0 0

this is question of combinations and permutations. Visualization helps but is not essential.

If there are 4 non-coplanar points say A, B,C, and D.

It takes 3 to make a plane.

Therefore:
ABC, ABD, ACD, BCD will make 4 unique planes given all points are non coplanar.

Notice that ABC, ACB, and CBA, etc are not listed because they are duplicates. This is why there is only 4, and not 24.

2007-08-31 17:07:21 · answer #5 · answered by Alan V 3 · 0 0

Geek has it right-4. While it does have to do with 3-d and vectors, the analysis uses neither. Simply define 4 points like EFGH and take them 3 at a time. You only have 4 combinations (order doesn't count).

2007-08-31 17:06:57 · answer #6 · answered by cattbarf 7 · 0 0

The points are A, B, C, and C, and combinations of any three of them: A,B,C; A,B,D; A,C,D; and B,C,D these 4 planes can be obtained.

2007-08-31 22:45:31 · answer #7 · answered by Pranil 7 · 0 0

4 . It`s also a permutation of four taking three at a time.

2007-08-31 17:12:39 · answer #8 · answered by J.SWAMY I ఇ జ స్వామి 7 · 0 0

If the points are A, B, C, and C, you can have four combinations of any three of them: A,B,C; A,B,D; A,C,D; and B,C,D.

2007-08-31 17:05:16 · answer #9 · answered by TitoBob 7 · 0 0

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