Y(3Y+Y+Y.Y)
Y times 3 y plus y times y squared...
2007-08-31 16:38:30 · 7 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
y (3y + y + y^2) = 0
factor out a y
y^2 (3 + 1 + y) = 0
y^2 (4 + y) = 0
set each one to 0
y^2 = 0
4 + y = 0 solve for y
y = 0
y = -4
2007-08-31 16:46:58 · answer #1 · answered by ? 4 · 0⤊ 2⤋
First clear up your question... You wrote in symbols
y times 3y plus y plus y squared.........y(3y+y+y^2) = 3y^2+y^2+ Y^3 = 4Y^2 + y^3
BUT you wrote
y times 3y plus y times y squared y(3y + y(y^2)) = y ( 3y + Y^3)=3Y^2+ Y^4
2007-08-31 23:59:39 · answer #2 · answered by ? 3 · 0⤊ 2⤋
To help you we need to know what the actual function is... The two ways you wrote your "equation" aren't even equal. 5y^3 is what the top one says, but the bottom simplifies to 4y^4... Repost your question and I'll try to help
2007-08-31 23:45:47 · answer #3 · answered by Lauren 3 · 0⤊ 2⤋
Uhhh, to have an equation, you need an equal sign.
2007-08-31 23:41:20 · answer #4 · answered by Anonymous · 1⤊ 2⤋
The Y's
2007-08-31 23:41:54 · answer #5 · answered by Anonymous · 0⤊ 2⤋
Is that an equation.
Shouldn't it have an equals sign ?
2007-08-31 23:41:41 · answer #6 · answered by Beardo 7 · 0⤊ 2⤋
assuming...
Y(3Y+Y+Y²) = 0
Y(4Y + Y²)=0
Y²(4+Y)=0
the zeros are: 0,0,-4
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2007-08-31 23:45:10 · answer #7 · answered by Alam Ko Iyan 7 · 0⤊ 2⤋