problem: find the point on the cirle (x-6)^2+(y-4)^2=25 where a line through (-4,-1) intersects the cirle and has the greatest slope. plz show work. thx
2007-08-31 14:50:52 · 2 answers · asked by NT 2 in Science & Mathematics ➔ Mathematics
circle has center at (6,4) and radius of 5
unless you want to solve simultaneous equations, draw the circle on graph paper and draw a line tangent to the circle through point (-4,-1). There are two possible lines, one with a positive slope and one with a negative slope. The positive slope is the greatest and should intersect the circle near the point (6,1)
2007-08-31 15:08:21 · answer #1 · answered by davidosterberg1 6 · 0⤊ 0⤋
Your point is (2,7)
slope = 4/3
Graphical solution using a 5 unit radius circle centered at (6,4) and the upper tangent line passing through (-4,-1)
2007-08-31 22:38:18 · answer #2 · answered by 037 G 6 · 0⤊ 0⤋