2007-08-31 14:42:53 · 5 answers · asked by beeboppinbippity 1 in Science & Mathematics ➔ Mathematics
| v | = (25 + 9 + 25)^(1/2)
| v | = (59)^(1/2)
| v | = 7.68 ( to 2 decimal places)
2007-09-04 10:41:58 · answer #1 · answered by Como 7 · 0⤊ 0⤋
The magnitude of any vector is equivalent to the square root of the square of each component.
The magnitude is visually equivalent to the line that connects the endpoint of the vector to the origin (they hypotenuse in 2-dimensions).
Thus the magnitude of this vector would be:
rt( (-5)^2 + (-3)^2 + 5^2 )
rt(25 + 9 + 25)
rt(59)
2007-08-31 21:50:10 · answer #2 · answered by Anonymous · 0⤊ 0⤋
sqrt( 5^2 + 3^2 + 5^2)
= sqrt(59)
2007-08-31 21:47:33 · answer #3 · answered by norman 7 · 0⤊ 0⤋
looks to be a 3d vector
square root of x^2+y^2+z^2=square root of 59 or 7.68
2007-08-31 22:42:39 · answer #4 · answered by James G 1 · 0⤊ 0⤋
v = <-5, -3, 5>
|v|=sqrt((-5)^2+(-3)^2+(5)^2_=sqrt(25+9+25)=sqrt(59)=7.68
2007-08-31 21:55:36 · answer #5 · answered by ptolemy862000 4 · 0⤊ 0⤋