2007-08-31 10:43:46 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3x-4y=32 ---equation 1
5x+2y=10---equation 2
Multiplying the 2nd equation with 2, we get 10x+4y=20
adding the first equation with this new equation we get,
13x=52
x= 4
then 20+2y=10 ----by putting value of x in equation 2
then y=-5
2007-08-31 10:49:48 · answer #1 · answered by S L 2 · 1⤊ 0⤋
I believe you mean solve 3x-4y over 5x+2y = 32 over 10.
Because you can't have more than one equal sign in a variable equation. As far as solving it? Honestly im too lazy to get a pen and paper right now. Sorry!
2007-08-31 17:51:51 · answer #2 · answered by Mike 2 · 0⤊ 1⤋
3x-4y=32 <--Eq 1
5x+2y=10 <-- Eq 2
10x +4y =20 <-- Eq 3 = 2*Eq 2
13x = 52 <-- Eq1 + Eq 3
x = 4
Put x=4 in Eq 1 getting:
3*4 -4y = 32
-4y = 32-12 = 20
y = -5
2007-08-31 17:52:05 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
first x (-5/3) and sum to the second
-5x+20y/3=-160/3
5x+2y=10
--------------------------
26y/3=-130/3 => 26y=-130 => y=-5
3x-4*(-5)=32 => 32-20=3x => 3x=12 => x= 4
Calculations checked (I hope not much people have seen my awful mistake solving :( ). Sorry.
2007-08-31 17:53:30 · answer #4 · answered by Neno Saturado 3 · 0⤊ 0⤋