I am having a hard time with this problem and the text isn't clear to me:
Solve:
(square root 4x + 4) + 12 = 0
2007-08-31 10:35:44 · 6 answers · asked by casper5 3 in Science & Mathematics ➔ Mathematics
Reading this as:
√4 x + 4 + 12 = 0 (ie as written)
2x + 16 = 0
2x = - 16
x = - 8
2007-09-04 10:28:44 · answer #1 · answered by Como 7 · 0⤊ 0⤋
First, factor out the 4 from under the square root,
sr(4(x+1) + 12 = 0 becomes 2sr(x+1) + 12 = 0
and 2sr(x+1) = -12 and sr(x+1) = -6 after dividing both sides.
sqare both sides get you (x+1) = 36 and x= 35 if you only use the negative square root. since the square root of 36 is actually plus or minus 6.
2007-08-31 10:47:25 · answer #2 · answered by Patrick S 3 · 0⤊ 0⤋
Sqrt(4x+4) + 12 = 0
sqrt(4x+4) = - 12
4x+4 = 144
4x = 140
x = 35
This works only if you take the negative sqrt(4x+4).
2007-08-31 10:46:14 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
square root(4x+4)= -12
Squaring both sides , gives
4x=4= 144
4x= 140
x= 35
2007-08-31 10:44:06 · answer #4 · answered by S L 2 · 0⤊ 0⤋
hm i should know this...
first, square everything under the square root sign. so u get 4x(^2)+16, then solve it like a regular equation.
4x^2+28(-28)=0(-28)
4x^2=0
and your done. ( i think- its been a while)
2007-08-31 10:42:10 · answer #5 · answered by Mike 2 · 0⤊ 2⤋
SQRT(4x) + 4 = 12
SQRT(4x) = 12 - 4 = 8
SQRT(4) times SQRT(x) = 8
2 times SQRT(x) = 8
SQRT(x) = 4
x = 4 times 4 = 16
2007-08-31 10:41:34 · answer #6 · answered by Anonymous · 0⤊ 2⤋