How do I solve using the Square Root Method?

Question

I'm having a hard time understanding the text:

Solve using Square Root Method.
x^2 + 5 = 41

Answer 1

x^2 + 5 = 41
x^2 = 41-5 =36
x = +/- sqrt(36) = +/- 6

Answer 2

Let collect like terms by subtracting 5 from both sides
X^2 =41-5
X^2=36
the radical symbol is a lot like the division symbol lets place the radical over the 36 to find the square root and the radical over x^2 to find the square root. By definition the square root of a number is that number times itself so we know that the square root of X^2 =x and now we have to find the square root of 36 well that =6 so here is the answer to the problem
x=6
now lets check it by putting it into the equation
6^2 + 5=41
36 + 5=41
Looks right to me what do you think....Good luck from the E..

Answer 3

x^2=36
X=6 or x=-6

Answer 4

Take the square root of both sides: Sq. Root ((x - 3) ^2) = Sq. root (36) x - 3 = +/- 6 x - 3 = 6, or x - 3 = -6 x = 9, or x = -3

Answer 5

x^2-36=0

(x-6)(6+x)=0
x=6 nd x=-6
x^2=36
x=-6and-6