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2007-08-31 08:52:32 · 6 answers · asked by garrett m 1 in Science & Mathematics ➔ Mathematics
ln(4)+2ln(x)+3ln(x^2+4)
= ln(4) + ln(x^2) + ln[(x^2+4)^3]
= ln [4*x^2*(x^2+4)^3]
A = 4x^2(x^2+4)^3
2007-08-31 08:57:03 · answer #1 · answered by Anonymous · 2⤊ 0⤋
ln A = ln(4) + 2ln(x) + 3ln(x^2 + 4)
rewrite as;
Ln A = ln {4 * x^2 * (x^2 + 4)^3}
Thus, A = 4x^2(x^2 + 4)^3
2007-08-31 09:00:18 · answer #2 · answered by Bear 2 · 0⤊ 0⤋
let ln(4) + 2ln(x) + 3ln(x^2 + 4) = ln (A)
ln(4)+ln(x^2)+ln(x^2 + 4)^3= ln (A) (since a ln(b) = ln(b)^a)
ln(4)(x^2)(x^2+4)^3 = ln(A) (since ln(a)+ln(b)+ln(c) = ln(abc))
4x^2(x^2 + 4) ^3 = A
4x^2(x^6 + 64 + 12 x^4 + 48 x^2 = A
4(x^8 + 12x^6 + 48 x^4 +64x^2) = A
2007-08-31 09:22:42 · answer #3 · answered by mohanrao d 7 · 0⤊ 0⤋
ln(4)+2ln(x)+3ln(x^2+4)
=ln(4)+ln(x)^2+ln(x^2+4)^3
=ln (4*x^2*(x^2+4)^3)
A=4*x^2*(x^2+4)^3
2007-08-31 09:07:13 · answer #4 · answered by iyiogrenci 6 · 0⤊ 0⤋
ln(4)+ ln(x^2)+ ln([x^2 +4]^3)
ln(4*(x^2)*(4+x^2)^3)
2007-08-31 08:59:43 · answer #5 · answered by Not Eddie Money 3 · 0⤊ 0⤋
=Ln(x^2+4)^3(4x^2)=LnA
A=4x^2(X^2+4)^3
2007-08-31 09:09:26 · answer #6 · answered by koh_arian 2 · 0⤊ 0⤋