Can anyone solve this problem?

Question

(3x^2+4x-1) (4) (2x-3)^3 (2) + (2x-3)^4 (6x+4)

I would appreciate step by step explinations

Thanks for your help

sorry i meant
simplify the expression above

The answer should be

2 (2x-3)^3 (2x+1) (9x+10)

I just want to see *how*

Answer 1

(3x^2 + 4x - 1)(4)(2x- 3)^3(2) + (2x - 3)^4(6x + 4)
First multiply the two coefficients '4' & '2' = '8' to the first bracketed term.
(8x^2 + 32x - 8)(2x - 3)^3 + (2x - 3)^4(6x + 4)
Take (2x - 3)^3 as a common factor

[(2x - 3)^3](8x^2 + 32x - 8) + {(2x - 3)(6x + 4)}
Multiply the pair of linear terms (curly brackets -RHS) together.

[(2x - 3)^3](8x^2 + 42x -8) +(12x^2 + 8x - 18x -12)
Remove curved brackets an add like terms.
[(2x - 3)^3][20x^2 + 32x -20]

Multiply out the cubic expression
[(2x)^3 -3(3)(2x)^2 + 3(3^2)(2x) - (3^3)][20x^2 + 32x - 20]
[8x^3 - 36x^2 + 54x - 27][20x^2 + 32x -20]
Multiply the two sets of square brackets together. This is a rather complex process, start by multiplying 8x^3 to each term in the other brackets. Then - 36x^2 to each term in the other brackets and so on. Then finally collect like terms.
160x^5 + 256x^4 - 160x^3
- 720x^4 - 1152x^3 + 720x^2
+1080x^3 +1728x^2 -1080x
- 540x^2 -864x + 540
_________________________________________
160x^5 - 464x^4 - 232x^3 + 1908x^2 - 1944x + 540
This is sol'n!!!!!

Answer 2

your qs is not clear!!!!
what should I do with that line????