Solve by using the quadratic formula?

Question

Solve by using the quadratic formula.
x^2=x+5

Answer 1

x^2=x+5

x² - x - 5 = 0

ax² + bx + c = 0
x = (-b ± √(b² - 4ac))/2a

x = (1 ± √(1 + 20))/2

x = (1 ± √(21))/2

x ≈ 2.79, x ≈ -1.79
.

Answer 2

This site shouldn't do your homework for you.

The quadratic formula is negative b plus or minus the square root of b squared minus 4AC all over 2A

Your equation should look like Ax^2 + Bx + C = 0

In your equation, A=1 B=-1 C=-5

Good luck.

Answer 3

rewrite to x^2 - x - 5 = 0

Quadratic formula is x = (-b +/1 sqrt( b^2 -4 a c))/(2 a)

a = 1, b = -1, c = -5.
Plug these values in and then done.

Answer 4

x²-x-5=0

x= [1±√(1+20)]/2
x = 1/2±√21/2

Answer 5

rewrite as x^2 - x -5 =0
now compare with ax^2 + bx+ c =0
a=1
b=-1
c=-5
the roots of this eqn by formula are
[-b + sqrt(b^2-4ac)/]2a
and
[-b - sqrt(b^2-4ac)/]2a

in this case it is

[1 + sqrt(1+20)]/2

and [1 - sqrt(21)]/2

wich are 2.79
and -1.79

Answer 6

x ² - x - 5 = 0
x = [ 1 ± √(1 + 20) ] / 2
x = [1 ± √(21) ] / 2
x = 2.79 , x = - 1.79