A. 12x^2+18
B. 5x^2+23x+18
C. 12x^2+6
D. 5x^2+7x+6
2007-08-31 03:30:04 · 8 answers · asked by BH 1 in Science & Mathematics ➔ Mathematics
B
5(x^2+4x)+3(x+6)
= 5*x^2 + 5*4x + 3*x + 3*6
= 5x^2 + 20x + 3x + 18
= 5x^2 + 23x + 18
the end
.
2007-08-31 03:36:23 · answer #1 · answered by The Wolf 6 · 1⤊ 0⤋
The solution is arrived at by the following steps:
1. Multiply 5 through the first term and 3 through the second term:
5x^2 + 20x + 3x + 18
2. Gather the terms of the same power:
5x^2 + 23x + 18
The answer is B.
2007-08-31 10:41:04 · answer #2 · answered by Joe S 6 · 0⤊ 0⤋
Common you can do this..........
Look at the equation after you multiply through
( 5x^2 + 20x ) + (3x + 18 ) Looking at this at once you can eliminate A and C.
All the coefficients have an x except 18
Now you can eliminate D
Heck you did not even have to add the equation together, which by the way give you 5x^2 + 23x + 18
2007-08-31 10:47:41 · answer #3 · answered by ? 3 · 0⤊ 0⤋
= 5(x^2 + 4x) + 3(x + 6)
= 5x^2 + 20x + 3x + 18
= 5x^2 + 23x + 18
Answer: B. 5x^2 + 23x + 18
2007-08-31 10:38:22 · answer #4 · answered by Jun Agruda 7 · 3⤊ 0⤋
expand;
5x^2+20x+3x+18
5x^2+23x+18
(B)
2007-08-31 10:41:02 · answer #5 · answered by cidyah 7 · 0⤊ 0⤋
b
distribute first than add like terms
2007-08-31 10:38:00 · answer #6 · answered by Milton C 3 · 0⤊ 0⤋
b
2007-08-31 10:44:27 · answer #7 · answered by 27ysq 4 · 0⤊ 0⤋
B
2007-08-31 10:40:35 · answer #8 · answered by Mugen is Strong 7 · 0⤊ 0⤋