Word problem?

Question

In a certain town, the demand for rental units was analyzed, and it was determined that, to meet the community's needs, builders would be required to build apartments in the following way: Every time they build three single-bedroom apartments, they should build four 2-bedroom apartments and one 3-bedroom apartment. Suppose a builder is planning to build a large apartment complex counting between 35 and 45 apartments. How many 1-bedroom apartments, 2-bedroom apartments, and 3-bedroom apartments would the apartment building contain?

Answer 1

So the builder is obligated to build in sets of 8 apartment units every time they build single bedroom units. That's 40 units. The remaining 5 can be any combination of 2 or 3 bedroom units.

Answer 2

Consider one 'unit'. That is three 1-bedrooms, four 2-bedrooms, and one 3-bedroom apartment.

That's 8 apartments, and satisfies all the quotas and ratios.

So take that 45 and divide by 8. That's five units plus 5 extra. 40 apartments is just exactly 8 units. 40 is within the range, so let's build 40 apartments, 8 units.

So that's 24 1-bedrooms (8 times 3), 32 2-bedrooms (8 times 4) and 8 3-bedrooms.

Answer 3

there are 8 groups of apartments that are built together (3 single bedrooms + 4 two bedrooms + 1 three bedroom=8apartments)
35/8 = 4.375 and 45/8 = 5.625
so it's safe to say that there will be a total of 5 lots of 8

therefore:
5 lots x 3 single rooms = 15 apartments
5 lots x 4 two bedrooms = 20 apartments
5 lots x 1 three bedroom = 5 apartments

with a total of 40 apartments

Answer 4

Build (6) sets of the 3 single bedroom, (24) 2 BR, and (6) 3 BR. Total of 36 apartments in the correct ratios.

Answer 5

s=single, d=double(two room) t=triple(three room)

3s:4d:1t

3+4+1= 8 apartments
8*5= 40

5*3s= 15 one-rooms, 5*4d= 20 two-rooms, 5*1t= 5 three-rooms

Answer 6

about...

15 1-bed
20 2-bed
5 3-bed