2 cars, heading towards each other, are 250 mi apart. If one car travels 45mph and the other 10 mph faster, in how many hours will the cars pass each other?
2007-08-30 18:54:06 · 6 answers · asked by steviewanger 1 in Science & Mathematics ➔ Mathematics
please explain
2007-08-30 19:01:35 · update #1
45x+(45+10)x=250 miles
45x+55x=250
100x=250
x=2.5hours
2007-08-30 19:02:16 · answer #1 · answered by swimmerkyle 2 · 0⤊ 0⤋
Distance = rate * time
Rate=45 mph for the first car, 55 mph for the second car
Time is unkown
250= 45t+55t
250= 100t
t= 250/100 or 2.5
2.5 hours
2007-08-31 02:03:49 · answer #2 · answered by Sher S 2 · 1⤊ 0⤋
d1 = 45t distance car1 travels in time t
d2 = 55t distance car2 travles in time t
The distance the 2 cars travel must equal 250 miles when the cars meet and pass each other. So:
d1 + d2 = 250 = 45t + 55t = 100t
So t = 2.5 hours
They will pass each other in 2 and one half hours
2007-08-31 02:18:59 · answer #3 · answered by Captain Mephisto 7 · 0⤊ 0⤋
They will take time
= 250/(45 + 45 + 10) hrs
= 2.5 hrs
distance /speed = time
2007-08-31 05:57:19 · answer #4 · answered by sv 7 · 0⤊ 0⤋
4 1/2 hrs
2007-08-31 01:59:40 · answer #5 · answered by Anonymous · 0⤊ 1⤋
2.5 hours
2007-08-31 02:20:17 · answer #6 · answered by Sky Chord 2 · 0⤊ 0⤋