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OK, the problem is:

8x^5+12x^3-6x^2-9

How do I factor it by grouping?

THANKS!

2007-08-30 18:49:15 · 3 answers · asked by Anahivette 2 in Science & Mathematics Mathematics

3 answers

Ok factor by grouping means "take out the common factors between two of the terms and then the other terms"

8x^5+12x^3-6x^2-9
Take out what is common between 8x^5, 12x^3 and 6x^2, 9

8x^5+12x^3 common factor: 4x^3
then, rewrite the terms 4x^3(2x^2+3)

Do the same to the other two terms
-6x^2-9 common factor: -3
-3(2x^2+3)

Now take what you got and write it together
4x^3(2x^2+3)-3(2x^2+3)

You can see that 4x^3 and -3 are being multiplied by the same things in parentheses, therefore you can combine them
leaving you with
(4x^3-3)(2x^2+3)

2007-08-30 18:59:58 · answer #1 · answered by Sher S 2 · 0 1

(4 x ³) (2 x ² + 3) - (3) (2 x ² + 3)
(2 x ² + 3) (4 x ³ - 3)

2007-08-31 03:31:57 · answer #2 · answered by Como 7 · 1 1

8x^5+12x^3 -6X^2-9
4X^3(2X^2+3) -3(2X^2+3)
(2X^2+3)(4X^3-3)

2007-08-31 02:44:11 · answer #3 · answered by Grampedo 7 · 0 1

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