solve for x:
square root of (x-8) = 3
i added 8 to both sides and got:
square root of x = 11
and squared both sides to get x = 121
is this right?
2007-08-30 18:12:44 · 5 answers · asked by iltwym_7591 2 in Science & Mathematics ➔ Mathematics
√(x - 8) = 3
Square both sides
x - 8 = 9
x = 17
2007-08-30 23:19:08 · answer #1 · answered by Como 7 · 1⤊ 1⤋
x= 9 + 8
2007-08-30 18:20:34 · answer #2 · answered by Anonymous · 0⤊ 1⤋
First step you did wrong. since (x-8) is under the square root, you cannot add 8. You must get rid of the square root. Which means squaring both sides.
(x-8) = 3^2 when you square a square root they cancel each other out and leave you with whatever is under the sign and in this case it is the (x-8).
(x-8)=9
x=8+9
x=17
2007-08-30 18:22:32 · answer #3 · answered by USMCBabydoll 2 · 1⤊ 1⤋
No...
Since x-8 is inside the (), you square both side first...
x-8 = 9
x = 17
sqrt of (17-8) = sqrt (9) = 3
2007-08-30 18:20:45 · answer #4 · answered by norman 7 · 0⤊ 1⤋
completely wrong
x = 17
2007-08-30 18:19:14 · answer #5 · answered by sm bn 6 · 0⤊ 1⤋