math question??

Question

how do u solve this problem?

(x+1) / 2 = (y+2) / 3 = (x+y) / 4

Answer 1

I think this question is a simultaneous equations.
Devide the equation into 2 equations.
(x+1)/2=(y=2)/3
(x+1)/2=(x+y)/4

From eq 2, find x in terms of y.
4x+4=2x+2y
4x-2x=2y-4
2x=2y-4
x=y-2

Sub x=y-2 to eq 1
3x+3=2y+4
3(y-2)+3=2y+4
3y-6+3=2y+4
3y-2y=4+3
y=7

Sub y=7 into eq x=y-2
x=(7)-2
x=5

There you go.
x=5 and y=7

To check your answer, just simply subtitute x=5 and y=7 into your original equation.

Answer 2

x=5, y = 7

find the lowest common denominator in this problem: in this case it is 12 (12 is divisible by 2, 3 and 4).
Multiply all the terms by 12. now you have
(12(x+1))/2 = (12(y+2)/3) = (12(x+y))/4
then you'll have
12X/2 +12/2 = 12Y/3 + 24/3 = 12X/4 + 12Y/4
which is
6X + 6 = 4Y + 8 = 3X + 3Y

Now start separating terms so you get one variable on one side of the equal sign, and the other variable on the other side.

6X + 6 = 4Y + 8 and 6X + 6 = 3X + 3Y
6X = 4Y + 2 and 3X + 6 = 3Y
4Y = 6X - 2 and 3Y = 3X + 6

This is known as 'two equations, two unknowns'
Did you follow how we got here? If not, you better ask your teacher for some basic help. Note: the "and" is really an =

You can subtract the second equation from the first one to get a single equation now.
4Y = 6X - 2
- 3Y = 3X + 6
---------------------------
y = 3X - 8

Now, just substitute this into one of the equations to reduce your two variables to one variable.

3Y = 3X + 6 and Y = 3X - 8 or 4Y = 6X - 2
so 3(3X - 8) = 3X + 6 4(3X - 8) = 6X -2
9X - 24 = 3X + 6 12X - 32 = 6X -2
6X = 30 6X = 30
X = 5

Now plug back into the equation to solve for Y
Y = 3X -8 and X = 5
so Y = 3(5) -8 = 15 - 8 = 7
Y = 7

Let's test it in the original problem
(5+1)/2 = (7+2)/3 = (5+7)/4
6/2 = 9/3 = 12/4
3 = 3 = 3




how about voting me best answer?

Answer 3

multiply by 12:

6(x + 1) = 4 (y + 2) = 3(x + y)

so 6x + 6 = 3x + 3y so 3x +6 = 3y so x +2 = y

6x + 6 = 4 (y +2) = 4( x +2 +2) = 4 (x + 4) = 4x +16
so 2x = 10
x = 5

y = 7

Answer 4

(x + 1)/2 = (y + 2)/3 = (x + y)/4 = k (say)
=> x + 1 = 2k, y + 2 = 3k, x + y = 4k
giving (2k -- 1) + (3k -- 2) = 4k => k = 3 then x + 1 = 2(3) => x = 5
y + 2 = 3(3) => y = 7

Answer 5

thats easy
x=5 and y=7
first multiply the whole thing by 12 so when all said and done looks like:
6x+6=4y+8=3x+3y
now, let us look at the latter two expressions:
4y+8=3x+3y
subtract 3y, and then subtract 8 so it looks like
y=3x-8
then we can look at the first two expressions and sub in this new y value.
6x+6=4y+8 becomes
6x+6=4(3x-8)+8
i think you should be able to solve for x here.
it turns out to be 5, and so you substitute 5 in for the equation we found earlier y=3x-8 to get
y=15-8
which is equal to 7

Answer 6

solve first equation:
(x+1)/2=(y+2)/3
3x+3=2y+4
3x-1=2y
second equation;
(x+1)/2=(x+y)/4
4x+4=2x+2y
2x+4=2y
then minus two equation,you got new equaion,
3x-1=2y minus 2x+4=2y
got x-5=0
x=5
y=7

Answer 7

3(x + 1) = 2(y + 2)
3x - 2y = 1 ------------> A

4(y + 2) = 3(x + y)
4y - 3y + 8 - 3x = 0
-3x + y = -8 -------------->B

Add A and B

-y = -7
y = 7

-3x = -15
x = 5

x = 5, y = 7

Answer 8

ummmm wow use a caculator jk look it up on google and it probably pop up

Answer 9

you write a giant question mark