ok I am confused.....Solve –9(x – 3)^2 = –7?

Question

Solve. –9(x – 3)^2 = –7.

Answer 1

(x - 3)^2 = 7/9
x - 3 = +/- sqrt(7)/3

x = sqrt(7)/3 + 3
or
x = -sqrt(7)/3 + 3

Answer 2

Step 1: Divide each side by -9-----------------(x-3)^2= 7/9
Step 2: take the sqrt of both sides --------sqrt (x-3)^2=sqrt 7/9
Step 3: when you sqrt each side the left side becomes
(x-3) why? remember sqrt is the same as raising something to the 1/2. the 1/2 and the 2 cancel each other out. One the right side you will have a positive and a negative sqrt 7/9
Step 4: add 3 to both sides so you have
x=+/- sqrt 7/9 + 3
Step 5: I am going to guess you are taking an Algebra II class which means your teacher will expect you to put the answer in proper form which means no fractions as the radicand.
x = +/- [(sqrt 7) /3] +3
Step 6: Standard form
x= 3 +/- [(sqrt 7) /3]

Answer 3

-9 (x - 3)^2 = -7

Divide both equations by -9, we'll get :

(x - 3)^2 = 7/9

square both equations, we'll get :

x - 3 = square root of 7/9

add 3 to both equations, we'll get :

x = 3 + 0.881917

x = 3.881917

To check, substitute the value of x, which is 3.881917

-9 (3.881917 - 3)^2 = -7
-9 (0.881917)^2 = -7
-9 (0.77777759488) = -6.99999835392 or -7

Answer 4

-9(x-3)^2 = -7
(x-3)^2 = 7/9
(x-3) = Sqrt(7/9)

x = 3 + sqrt(7/9) or 3 - sqrt(7/9)

Answer 5

(x - 3) ² = 7 / 9
(x - 3) = ( ± √7 ) / 3
x = 3 ± (√7) / 3

Answer 6

-- 9(x -- 3)^2 = -- 7
=> (x -- 3)^2 = 7/9
=> x -- 3 = sqrt(7/9) or --sqrt(7/9)
=> x = 3 + sqrt(7/9) or 3 -- sqrt(7/9)

Answer 7

-9(x^2 -6x +9) = -7
-9(x-3)(x-3) = -7
(-9x + 27) (x-3) = -7

From (-9x + 27) = -7
-9x + 27= -7
-9x= -7 -27
-9x = -34
x = 34/9

From (x - 3) = -7
x-3= -7
x = -7 +3
x = -4


Therefore, the answers are x= 34/9 and -4

Answer 8

x=(sq rt. 7/9) +3

first divide by -9 on both sides
then square root both sides
then add 3. bam u have it