math question? (substitution)?

Question

Please show me how u solve this by using substitution
thanks.

2y = 3x - 2
4 = 2y - x

Answer 1

you know that 2y = 3x -2, hence replace the 2y in the second equation by 3x - 2

4 = 3x - 2 - x = 2x - 2
2x = 6 => x = 3

thus 2y = 9 - 2 = 7 and y = 3.5

Answer 2

Rewrite the second equation as
x = 2y - 4
Then substitute this into the first equation:
2y = 3(2y-4) - 2
<=> 2y = 6y - 12 - 2
<=> 4y = 14
<=> y = 7/2
and then since x = 2y - 4 we have x = 2(7/2) - 4 = 7-4 = 3.
So x = 3 and y = 7/2. You can check that this solution satisfies both original equations.

Answer 3

2y = 3x - 2 >>>>>>equation 1
4 = 2y - x >>>>>>equation 2

From equation 2,
4 = 2y - x
x = 2y - 4 >>>>>>equation 3

Subsitute into equation 1.
2y = 3(2y - 4) - 2
2y = 6y - 12 - 2
2y - 6y = -14
-4y = -14
y = -14 / -4
y = 3.5

Subsitute y = 3.5 into equation 3.
x = 2y - 4
x = 2(3.5) - 4
x = 7 - 4
x = 3

Thus x = 3 , y = 3.5

Answer 4

x = 2y - 4
2y = 3(2y - 4) - 2
2y = 6y - 12 - 2
2y = 6y - 14
4y = 14
y = 7 / 2

x = 7 - 4
x = 3

x = 3 , y = 7 / 2

Answer 5

4=2y-x
2y=-x-4
y=-x/2-2

so
2(-x/2-2)=3x-2

and you solve for x from there
once you have the value of x, put it in either of the equations and solve for y

Answer 6

4 = 2y - x
2 - x = y

2(2 -x) = 3x -2
4x - 2x = 3x - 2
x = 2