the counterclockwise angle the vector difference?

Question

Find the counterclockwise angle the vector difference Vector B- Vector A makes with the +x axis
VectorB-VectorA=6.83cm
Problem 1.45
Vector A has components Ax = 1.29 , Ay = 2.43 ; vector B has components Bx = 4.17 , By = -3.76 .

well unfortunately that is how the question is stated on my homework, which explains why i need help with it. But thanks for your concern..

Answer 1

Usually, people can answer questions in this physics section if they're asked in a coherent fashion.

Unfortunately, that is NOT so in the present case.

Live long and prosper.

[Edit: I confess that I was thrown by missing words like "of" and "that," and by the mistatement that "VectorB-VectorA=6.83cm." That is mathematically wrong. What is meant is that the LENGTH or MODULUS |VectorB-VectorA| = 6.83cm. If this question was indeed set as stated, whoever set it needs to be reminded of these things.

I agree with the solution below, with one correction. The COUNTERCLOCKWISE angle is + 65.049 degrees; if you go - 65.049 degrees in a counterclockwise direction, you'll be going clockwise and end up in the first quadrant.]

Answer 2

Not all that difficult, doc.
B - A = (2.88, -6.19)
Magnitude = sqrt(2.88^2 + -6.19^2) = 6.8272
Angle = arctan(-6.19/2.88) = -1.1353 rad = - 65.049 deg.