For the dragster whose wheels roll without slipping, is there a relationship between the magnitude a (in m/s2)

Question

Two identical dragsters, starting from rest, accelerate side-by-side along a straight track. The wheels on one of the cars roll without slipping, while the wheels on the other slip during part of the time.
For the dragster whose wheels roll without slipping, is there a relationship between the magnitude a (in m/s2) of its linear acceleration and the magnitude α (in rad/s2) of the angular acceleration of its wheels?
a) Yes. The relationship is a= alpha^2 / r, where r (in m) is the radius of a wheel.
b) Yes. The relationship is alpha= ra, where r (in m) is the radius of a wheel.
c) no
d) Yes. The relationship is a= r alpha, where r (in m) is the radius of a wheel.

Answer 1

d. Just as with velocity or displacement, every (rad/s^2, rad/s, rad) results in the rim motion of r times that quantity. By definition, the arc length of 1 radian is equal to the distance of the arc from the center, i.e., the radius.