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Two identical dragsters, starting from rest, accelerate side-by-side along a straight track. The wheels on one of the cars roll without slipping, while the wheels on the other slip during part of the time.
For the dragster whose wheels roll without slipping, is there a relationship between its linear speed v (in m/s) and the angular speed ω (in rad/s) of its wheels?
a) Yes. The relationship is V=r w , where r (in m) is the radius of a wheel.
b) No
c) Yes. The relationship is w=r v , where r (in m) is the radius of a wheel.
d) Yes. The relationship is w=v^2 / r, where r (in m) is the radius of a wheel.

2007-08-30 16:27:24 · 1 answers · asked by Anonymous in Science & Mathematics Physics

1 answers

Answer is a). Think about it. w is in rad/sec. Each rad of rotation moves the car 1 wheel radius r. So velocity V = r*w.

2007-08-30 16:35:18 · answer #1 · answered by kirchwey 7 · 0 0

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